SQLLEFT JOIN 关键字从左表 ( table1 )返回所有的行,即使右表 ( table2 ) 中没有匹配。如果右表中没有匹配,则结果为 NULL
SELECT column_name(s) FROM table1 LEFT JOIN table2 ON table1.column_name = table2.column_name;
在某些数据库中,LEFT JOIN 称为 LEFT OUTER JOIN
SELECT column_name(s) FROM table1 LEFT OUTER JOIN table2 ON table1.column_name = table2.column_name;
如果不理解,那么就看图解
假设我们有两张表 A 和 B
可以看到每个表的最后一条记录是不匹配的,那么 LEFT JOIN 的结果就是
演示数据
先在 MySQL 数据库运行下面的语句创建测试数据
CREATE DATABASE IF NOT EXISTS ddkk default character set utf8mb4 collate utf8mb4_unicode_ci;
USE ddkk;
DROP TABLE IF EXISTS lession;
DROP TABLE IF EXISTS lession_views;
CREATE TABLE lession (
id int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT,
name varchar(32) default '',
views int(11) NOT NULL default '0',
created_at DATETIME
);
CREATE TABLE lession_views (
uniq bigint(20) primary key NOT NULL default '0' ,
lession_id int(11) default '0',
date_at int(11) NOT NULL default '0',
views int(11) NOT NULL default '0'
);
INSERT INTO lession(id,name,views,created_at) VALUES
(1, 'Python DDKK.COM 弟弟快看',981,'2017-04-18 13:52:03'),
(3, 'Ruby DDKK.COM 弟弟快看',199,'2017-05-01 06:16:14'),
(4, 'SQL DDKK.COM 弟弟快看', 300,'2017-05-02 08:13:16');
INSERT INTO lession_views(uniq,lession_id,date_at,views) VALUES
(20170511000001,1,20170511,320),
(20170511000002,2,20170511,22),
(20170511000003,3, 20170511,49),
(20170512000001,1,20170512,220),
(20170512000002,2,20170512,12),
(20170512000003,3,20170512,63),
(20170513000001,1,20170513,441),
(20170513000002,2,20170513,39),
(20170513000003,3,20170513,87);
使用SELECT * FROM lession; 运行结果如下
mysql> SELECT * FROM lession;
+----+---------------------+-------+---------------------+
| id | name | views | created_at |
+----+---------------------+-------+---------------------+
| 1 | Python DDKK.COM 弟弟快看 | 981 | 2017-04-18 13:52:03 |
| 3 | Ruby DDKK.COM 弟弟快看 | 199 | 2017-05-01 06:16:14 |
| 4 | SQL DDKK.COM 弟弟快看 | 300 | 2017-05-02 08:13:16 |
+----+---------------------+-------+---------------------+
使用SELECT * FROM lession_views; 运行结果如下
mysql> SELECT * FROM lession_views;
+----------------+------------+----------+-------+
| uniq | lession_id | date_at | views |
+----------------+------------+----------+-------+
| 20170511000001 | 1 | 20170511 | 320 |
| 20170511000002 | 2 | 20170511 | 22 |
| 20170511000003 | 3 | 20170511 | 49 |
| 20170512000001 | 1 | 20170512 | 220 |
| 20170512000002 | 2 | 20170512 | 12 |
| 20170512000003 | 3 | 20170512 | 63 |
| 20170513000001 | 1 | 20170513 | 441 |
| 20170513000002 | 2 | 20170513 | 39 |
| 20170513000003 | 3 | 20170513 | 87 |
+----------------+------------+----------+-------+
SQL LEFT JOIN 范例
假设我们要查看所有已经存在的课程的每天的访问量,那么可以使用下面的 SQL 语句
SELECT lession.id,lession.name,lession_views.date_at, lession_views.views FROM lession LEFT JOIN lession_views ON lession.id=lession_views.lession_id ORDER BY lession.id DESC;
输出结果如下
mysql> SELECT lession.id,lession.name,lession_views.date_at, lession_views.views FROM lession LEFT JOIN lession_views ON lession.id=lession_views.lession_id ORDER BY lession.id DESC;
+----+---------------------+----------+-------+
| id | name | date_at | views |
+----+---------------------+----------+-------+
| 4 | SQL DDKK.COM 弟弟快看 | NULL | NULL |
| 3 | Ruby DDKK.COM 弟弟快看 | 20170511 | 49 |
| 3 | Ruby DDKK.COM 弟弟快看 | 20170512 | 63 |
| 3 | Ruby DDKK.COM 弟弟快看 | 20170513 | 87 |
| 1 | Python DDKK.COM 弟弟快看 | 20170511 | 320 |
| 1 | Python DDKK.COM 弟弟快看 | 20170512 | 220 |
| 1 | Python DDKK.COM 弟弟快看 | 20170513 | 441 |
+----+---------------------+----------+-------+