【LeetCode】36. Valid Sudoku 解题报告(Python)
题目地址:https://leetcode.com/problems/valid-sudoku/description/
题目描述:
Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
1、 Eachrowmustcontainthedigits1-9withoutrepetition.;
2、 Eachcolumnmustcontainthedigits1-9withoutrepetition.;
3、 Eachofthe93x3sub-boxesofthegridmustcontainthedigits1-9withoutrepetition.;
Apartially filled sudoku which is valid.
TheSudoku board could be partially filled, where empty cells are filled with the character '.'.
Example 1:
Input:
[
["5","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: true
Example 2:
Input:
[
["8","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being
modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Note:
1、 ASudokuboard(partiallyfilled)couldbevalidbutisnotnecessarilysolvable.;
2、 Onlythefilledcellsneedtobevalidatedaccordingtothementionedrules.;
3、 Thegivenboardcontainonlydigits1-9andthecharacter'.'.;
4、 Thegivenboardsizeisalways9x9.;
题目大意
判断一个9*9的二维数组是不是一个有效的数独。只用判断有效即可,即题目中的三个条件,不用求解。
解题方法
如果只判断有效的话,实现三个函数分别对应三个条件即可:判断行,判断列,判断9宫格。
把要判断的这些位置的数字取出来,然后用set后的长度是否等于原长度就能知道是不是有重复数字了。题目中已经说了给出的数字只有1~9,所以省掉了很多事。判断之前需要把'.'给去掉,因为数字只允许出现一次,而'.'可能出现多次。
时间复杂度是O(N^2),空间复杂度是O(N).
代码如下:
class Solution(object):
def isValidSudoku(self, board):
"""
:type board: List[List[str]]
:rtype: bool
"""
n = len(board)
return self.isValidRow(board) and self.isValidCol(board) and self.isValidNineCell(board)
def isValidRow(self, board):
n = len(board)
for r in range(n):
row = [x for x in board[r] if x != '.']
if len(set(row)) != len(row):
return False
return True
def isValidCol(self, board):
n = len(board)
for c in range(n):
col = [board[r][c] for r in range(n) if board[r][c] != '.']
if len(set(col)) != len(col):
return False
return True
def isValidNineCell(self, board):
n = len(board)
for r in range(0, n, 3):
for c in range(0, n, 3):
cell = []
for i in range(3):
for j in range(3):
num = board[r + i][c + j]
if num != '.':
cell.append(num)
if len(set(cell)) != len(cell):
return False
return True
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