题目地址:https://leetcode-cn.com/contest/weekly-contest-185/problems/reformat-the-string/

题目描述

给你一个数组 orders,表示客户在餐厅中完成的订单,确切地说, orders[i]=[customerNamei,tableNumberi,foodItemi] ,其中 customerNamei 是客户的姓名,tableNumberi 是客户所在餐桌的桌号,而 foodItemi 是客户点的餐品名称。

请你返回该餐厅的 点菜展示表 。在这张表中,表中第一行为标题,其第一列为餐桌桌号 “Table” ,后面每一列都是按字母顺序排列的餐品名称。接下来每一行中的项则表示每张餐桌订购的相应餐品数量,第一列应当填对应的桌号,后面依次填写下单的餐品数量。

注意:客户姓名不是点菜展示表的一部分。此外,表中的数据行应该按餐桌桌号升序排列。

示例1:

输入:orders = [["David","3","Ceviche"],["Corina","10","Beef Burrito"],["David","3","Fried Chicken"],["Carla","5","Water"],["Carla","5","Ceviche"],["Rous","3","Ceviche"]]
输出:[["Table","Beef Burrito","Ceviche","Fried Chicken","Water"],["3","0","2","1","0"],["5","0","1","0","1"],["10","1","0","0","0"]] 
解释:
点菜展示表如下所示:
Table,Beef Burrito,Ceviche,Fried Chicken,Water
3    ,0           ,2      ,1            ,0
5    ,0           ,1      ,0            ,1
10   ,1           ,0      ,0            ,0
对于餐桌 3:David 点了 "Ceviche" 和 "Fried Chicken",而 Rous 点了 "Ceviche"
而餐桌 5:Carla 点了 "Water" 和 "Ceviche"
餐桌 10:Corina 点了 "Beef Burrito" 

示例2:

输入:orders = [["James","12","Fried Chicken"],["Ratesh","12","Fried Chicken"],["Amadeus","12","Fried Chicken"],["Adam","1","Canadian Waffles"],["Brianna","1","Canadian Waffles"]]
输出:[["Table","Canadian Waffles","Fried Chicken"],["1","2","0"],["12","0","3"]] 
解释:
对于餐桌 1:Adam 和 Brianna 都点了 "Canadian Waffles"
而餐桌 12:James, Ratesh 和 Amadeus 都点了 "Fried Chicken"

示例3:

输入:orders = [["Laura","2","Bean Burrito"],["Jhon","2","Beef Burrito"],["Melissa","2","Soda"]]
输出:[["Table","Bean Burrito","Beef Burrito","Soda"],["2","1","1","1"]]

提示:

1、 1<=orders.length<=5*10^4
2、 orders[i].length==3
3、 1<=customerNamei.length,foodItemi.length<=20
4、 customerNameifoodItemi由大小写英文字母及空格字符''组成;
5、 tableNumberi是1到500范围内的整数;

题目大意

给出了Table 和 food 的一些匹配关系,求每条边出现的次数,以形成一张表格。

解题方法

字典统计边的次数

这个题本身不难,但是比较恶心,因为要返回的结果必须是指定格式的。所以我的代码写的贼麻烦。

1、 统计foods和tables分别为多少,并进行排序;
2、 统计每个桌的各个菜的次数;
3、 把所有的桌的菜按照顺序拼接成列表;

Python代码如下:

class Solution:
    def displayTable(self, orders: List[List[str]]) -> List[List[str]]:
        count = collections.defaultdict(dict)
        foods = set()
        tables = set()
        for order in orders:
            foods.add(order[2])
            tables.add(int(order[1]))
        foods = sorted(list(foods))
        cols = ["Table", ] + foods
        res = []
        res.append(cols)
        for order in orders:
            if order[2] not in count[order[1]]:
                count[order[1]][order[2]] = 0
            count[order[1]][order[2]] += 1
        for table in sorted(list(tables)):
            table = str(table)
            tc = count[table]
            line = [table,]
            for food in foods:
                if food not in tc:
                    line.append("0")
                else:
                    line.append(str(tc[food]))
            res.append(line)
        return res

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